16÷6怎么用竖式计算 计算： |-3|+16÷(-2 ) 3 +(2009-π ) 0 - 3 tan60°

计算： |-3|+16÷(-2 ) 3 +(2009-π ) 0 - 3 tan60°  

计算： |-3|+16÷(-2 ) 3 +(2009-π ) 0 - 3 tan60°

=3-2+1-3
=-1．

x+y+z=0求 x3+y3+z3=？

(x+y+z)^3=0
如果你不知道三项的展开式的话 先把x+y看成一项
（x+y+z）^3
=(x+y)^3+z^3+3(x+y)^2z+3(x+y)z^2
=x^3+y^3+z^3+3x^2y+3xy^2+3(x+y)^2z+3(x+y)z^2
=x^3+y^3+z^3+3xy(x+y)+3(x+y)^2z+3(x+y)z^2
=x^3+y^3+z^3+3(x+y)[xy+(x+y)*z+z^2]
=x^3+y^3+z^3+3(x+y)(xy+xz+yz+z^2)
=x^3+y^3+z^3+3(x+y)(x+z)(y+z)
=0
x^3+y^3+z^3=-3(x+y)(x+z)(y+z)
x+y+z=0
x+y=-z
y+z=-x
x+z=-y
x^3+y^3+z^3=3
按你的意思我只能算出这个结果 不给的乘积 没办法算出具体值

计算：（2a） 3 =______；-3x（2x-3y）=______

(-5）的3次幂除以（-3）的3次幂

(-5）的3次幂除以（-3）的3次幂=(-125)÷(-27)=125/27

2√12-3√27+3√1/3 怎么算

2√12-3√27+3√1/3
=4√3-9√3+√3
=-4√3

-9÷3+(1/2-2/3)*12+(-3)^2

=-3+(3/6-4/6)*12+9
=-3+(1/6)*12+9
=-3+2+9
=8

(-1/2a^2 b^3)^3乘（-2a^2 b）^3=

(-1/2a^2 b^3)^3乘（-2a^2 b）^3
=-1/8a^6 b^9乘（-8a^6 b^3)
=a^12b^12

lim(x→3)(x^2-4x+3)/[sin(x-3)]

原式=lim(x→3)(x-3)(x-1)/sin(x-3)
=lim(x→3)(x-1)[(x-3)/sin(x-3)]
=(3-1)*1
=2

(a+1)²(2a-3)-2(a+1)(3-2a)+2a-3

(a+1)²(2a-3)-2(a+1)(3-2a)+2a-3
=(a+1)²(2a-3)+2(a+1)(2a-3)+2a-3
=(2a-3)((a+1)²+2(a+1)+1)
=(2a-3)(a+1+1)²
=(2a-3)(a+2)²

3a的3次方-6a的平方+3a

3a³-6a²+3a
=3a（a²-2a+1）
=3a（a-1）²