cos2xcosx化简 先化简分式[(3x/x-1)-(x/1+x)]/(x/1-x²)
先化简分式[(3x/x-1)-(x/1+x)]/(x/1-x²)
先化简分式[(3x/x-1)-(x/1+x)]/(x/1-x²)
x-3x+6≥2
x≤2
4x-2<5x+1
x>-3
-3<x≤2
原式=[3x(x+1)-x(x-1)]/(x-1)(x+1)×(1-x²)/x
=-(3x²+3x-x²+x)/(1-x²)×(1-x²)/x
=-(2x²+4x)/x
=-2x-4
分母不等于0
所以取x=2
原式=-4-4=-8
先化简分式(3x/x-1 -x/x-1)÷x/x平方-1,再在-3<x≤2范围内取一个合适的数字代入
化简:(3x/x-1 -x/x-1)÷x/x²-1=2x/(x-1)]*[(x+1)(x-1)/x]=2(x+1),
在-3<x≤2范围内,因为x≠0,和±1,取x=2,代入,原式=6,
若取x=-2代入,则 原式=-2。
化简分式【(x/x+1)+(x/x^2-1)】/(x^2+x/x^2+2x+1)
解:
[(x/x+1)+(x/x²-1)]/(x²+x/x²+2x+1)
=[x(x-1)/(x²-1)+x/(x²-1)]/[x(x+1)/(x+1)²]
=x²/(x²-1)/[x/(x+1)]
=x/(x-1)
如仍有疑惑,欢迎追问。 祝:学习进步!
化简分式 (1)x²+x/x²-1 (2)x²-9/x²-6x+9
x²+x/x²-1 =x(x+1)/(x+1)(x-1)=x/(x-1)
x²-9/x²-6x+9 =(x+3)(x-3)/(x-3)^2=(x+3)/(x-3)
化简 (3x/x-1 -x/x+1)÷x/x²-1
=【3x(x+1)-x(x-1)]/(x+1)(x-1) ×(x+1)(x-1)/x
=(3x²+3x-x²+x)/x
=4
3x/x-1-2(1+1/x-1)²=x/x+1的结果 3x/x-1-2(1+1/x-1)²=x/x+1的结果
两边乘(x-1)²(x+1)
3x(x+1)(x-1)-2x²(x+1)=x(x-1)²
3x³-3x-2x³-2x²=x³-2x²+x
-3x=x
x=0
![cos2xcosx化简 先化简分式[(3x/x-1)-(x/1+x)]/(x/1-x²)](http://img.zhputi.com/uploads/1a3d/1a3d7a47a35aee993dd56b084e62e56f19297.jpg)
化简分式[x/(x+1)-2/(x^2-1)]÷(x^2-4)/(x^2-2x+1)
解
原式
=[x(x-1)/(x-1)(x+1)-2/(x+1)(x-1)]÷(x-2)(x+2)/(x-1)²
=[(x²-x-2)/(x-1)(x+1)]×(x-1)²/(x-2)(x+2)
=(x-2)(x+1)/(x-1)(x+1)×(x-1)²/(x-2)(x+2)
=(x-2)/(x-1)×(x-1)²/(x-2)(x+2)
=(x-1)/(x+2)
化简(1/x-1 - 1/x1)/ x/2x²²-2
(1/x-1 - 1/x1)/ x/2x22-2
=(x/x2-x - x-1/x2-x ) × 2x2-2/x
=1/x2-x × 2x2-2/x
=1/x(x-1) ×2(x-1)(x+1)
=2(x+1)/x2
=2x+2/x2
[﹙x/x+1﹚+1]÷[1-﹙3x²/1-x²﹚]×﹙1/x-1﹚,其中x=4的负1次方?
x=4^(-1)
x=1/4
[x/(x+1)+1]÷[1-3x²/(1-x²)]×1/(x-1)
=[x/(x+1)+1]÷[1+3x²/(x²-1)]×1/(x-1)
=[(x+x+1)/(x+1)]÷[(x²-1+3x²)/(x²-1)]×1/(x-1)
=[(2x+1)/(x+1)]÷[(4x²-1)/(x²-1)]×1/(x-1)
=(2x+1)/(x+1)×(x²-1)/(4x²-1)×1/(x-1)
=(2x+1)/(x+1)×(x-1)(x+1)/(2x-1)(2x+1)×1/(x-1)
=(2x+1)/(x+1)×(x+1)/(2x-1)(2x+1)
=(2x+1)×1/(2x-1)(2x+1)
=1/(2x-1)
=1/(2*1/4-1)
=1/(-1/2)
=-2
先化简,再求值:(x²-1)/(x²+2x+1)÷(x-1)/(x+1)-x/(x+1),其中x=根号2-1
(x²-1)/(x²+2x+1)÷(x-1)/(x+1)-x/(x+1),其中x=根号2-1
=(x-1)(x+1)/(x+1)²÷(x-1)/(x+1)-x/(x+1)
=(x-1)/(x+1)÷(x-1)/(x+1)-x/(x+1)
=1-x/(x+1)
=(x+1-x)/(x+1)
=1/(x+1)
=1/(√2-1+1)
=1/√2
=√2/(√2*√2)
=1/2(√2)