分式化简 化简分式:2a2+3a+2a+1?a2?a?5a+2?3a2?4a?5a?2+2a2?8a+5a?3
化简分式:2a2+3a+2a+1?a2?a?5a+2?3a2?4a?5a?2+2a2?8a+5a?3
化简分式:2a2+3a+2a+1?a2?a?5a+2?3a2?4a?5a?2+2a2?8a+5a?3
2a2+3a+2 a+1 ? a2?a?5 a+2?
3a2?4a?5 a?2+
2a2?8a+5 a?3=(2a+1)+
1 a+1-(a-3)-
1 a+2-(3a+2)+
1 a?2+(2a-2)-

1 a?3
=[(2a+1)-(a-3)-(3a+2)+(2a-2)]+(
1 a+1-
1 a+2+
1 a?2-
1 a?3)
=
-
1 a+2+
1 a?2-
1 a?3=
1 (a+1)(a+2)-
1 (a?2)(a?3)=
?8a+4 (a+1)(a+2)(a?2)(a?3).
a4+b4+c4-2a2b2-2b2c2-2c2a2怎样分解因式?
=(a^2-b^2-c^2)^2-4b^2c^2
=(a^2-b^2-c^2+2bc)(a^2-b^2-c^2-2bc)
=(a^2-(b-c)^2)(a^2-(b+c)^2)
=(A+B-C)*(A-B+C)*(A+B+C)*(A-B-C)
已知丨x-2丨+(1/2y+2)^2=0,求(x^3y^2+2x^2y^3)/(1/2xy^2)的值
已知丨x-2丨+[(1/2)y+2]²=0,求(x³y²+2x²y³)/[(1/2)xy²]的值
由条件可知:x=2,y=-4;因此(x³y²+2x²y³)/[(1/2)xy²]=2x(x+2y)=4(2-8)=-24
观察下列等式:3 2 -1 2 =8=8×1;5 2 -3 2 =16=8×2;7 2 -5 2 =24=8×3;9 2 -7 2 =32=8×4…这些等式
(1)(2n+1) 2 -(2n-1) 2 =8n;(2)(2n+1) 2 -(2n-1) 2
=4n 2 +4n+1-(4n 2 -4n+1)
=8n;
即(2n+1) 2 -(2n-1) 2 =8n,
故两个连续奇数的平方差是8的倍数.
因式分解:2m^2n^2+8mn+8+x(mn+2)^2 因式分解:(a-b)^2(3a-2)+(2-3a)a^2
原式=2(m²n²+4mn+8)+x(mn+2)²
=2(mn+2)²+x(mn+2)²
=(mn+2)²(x+2)
原式=(a-b)²(3a-2)-a²(3a-2)
=(3a-2)[(a-b)²-a²]
=(3a-2)(a-b+a)(a-b-a)
=-b(3a-2)(2a-b)
已知A=2x^2-,B=y^2-z^2+,C=-x^2+2Y^2-,且(x+1)^2+|y+1|+|z|=0.求A-(2B
因为(x+1)^2+|y+1|+|z|=0
又因为(x+1)^2≥0,|y+1|≥0,|z|≥0
所以x=-1,y=-1,z=0
所以 A-(2B-3C)
=2x^2--[2(y^2-z^2+)-3(-x^2+2y^2-)]
=2x^2--2y^2+2z^2-2-3x^2+6y^2-3
=-x^2+4y^2+2z^2-6
=-1+4+0-0
=3
下列运算中,正确的是( ) A.2a 2 +3a 2 =a 4 B.5a 2 -2a 2 =3 C.a 3 ×2a 2 =2a 6 D.3a
A、2a 2 +3a 2 =5a 2 ,故本选项错误;B、5a 2 -2a 2 =3a 2 ,故本选项错误;
C、a 3 ×2a 2 =2a 5 ,故本选项错误;
D、3a 6 ÷a 2 =3a 4 ,故本选项正确.
故选D.
计算题:(1)(-2a 3 b 2 c) 3 ÷(4a 2 b 3 ) 2 -a 4 c?(-2ac 2 );(2)(3x 2 +4x-1)(3x 2 -4x
(1)原式=(-8a 9 b 6 c 3 )÷(16a 4 b 6 )+2a 5 c 3= 1 2 a 5 c 3 +2 a 5 c 3
= 3 2
a 5 c 3
(2)原式=(3x 2 -1) 2 -16x 2
=9x 4 -6x 2 +1-16x 2
=9x 4 -22x 2 +1
(3)原式=a 3 +a 2 +a-2a 2 -2a-2+(a 2 -3)(1-a)
=a 3 +a 2 +a-2a 2 -2a-2+a 2 -a 3 -3+3a
=2a-5
(4)原式=16-8+(-0.125)15×8 15 +2 2n ÷2 2n-2 =8+(-0.125×8) 15 +4=8-1+4=11.
故答案为
a 5 c 3 、9x 4 -22x 2 +1、2a-5、11.
化简:(1)7-3x-4x2+4x-8x2-15 (2)-2(2ab-a2)+3(2a2-ab)-4(3a2...
(1)原式=-12x2+x-8
(2)原式=-4ab+2a2+6a2-3ab-12a2+8ab
=-4a2+ab
(3)原式=5a2b-2ab2+3(ab2-a2b)
=5a2b-2ab2+3ab2-3a2b
=2a2b+ab2.
先化简再求值:(2a?2ba2?2ab+b2+ba2?b2)÷3b+2aa?b,其中a=5,b=2
原式=[
2(a?b) (a?b)2+
b (a+b)(a?b)]?
a?b 3b+2a=
2(a+b)(a?b)+b(a?b) (a+b)(a?b)2?
a?b 3b+2a=
(a?b)(3b+2a) (a+b)(a?b)2?
a?b 3b+2a=
1 a+b,
当a=5,b=2时,原式=
.