如何把一个数因式分解 把 (x-1)(x+3)+5 因式分解

把 (x-1)(x+3)+5 因式分解  

把 (x-1)(x+3)+5 因式分解

(x-1)(x+3)+5
=x²+2x-3+5
=x²+2x+2
无法分解因式
您好，答题不易
如有帮助请采纳，谢谢

因式分解(x-1)(x+5)(x+3)+12

(x^2-1)(x+3)(x+5)+12
=(x+1)(x-1)(x+3)(x+5)+12
=[(x-1)(x+5)][(x+3)(x+1)]+12
=(x^2+4x-5)(x^2+4x+3)+12
=[(x^2+4x-1)-4][(x^2+4x-1)+4]+12
=(x^2+4x-1)^2-16+12
=(x^2+4x-1)^2-4
=(x^2+4x-1+2)(x^2+4x-1-2)
=(x^2+4x+1)(x^2+4x-3).
是否可以解决您的问题？

（x+3）*（x-1）=x+3 用因式分解

（x+3）*（x-1）=x+3
（x+3）*（x-1）-（x+3）=0
(x+3)(x-1-1)=0
(x+3)(x-2)=0
x1=-3 x2=2

(x-1)(x+3)+1因式分解

(x-1)(x+3)+1
=x^2+2x-3+1
=x^2+2x-2
=(x-1+√5)(x-1-√5)

[X-1][X+1][X+3][X+5]+15，把上式因式分解

原式=[(x+1)(x+3)][(x-1)(x+5)]+15
=[(x²+4x)+3][(x²+4x)-5]+15
=(x²+4x)²-2(x²+4x)-15+15
=(x²+4x)²-2(x²+4x)
=(x²+4x-2)x(x+4)
=x(x²+4x-2)(x+4)

（X-1）(X+1)（X+3）（X+5）-20 因式分解

(x-1)(x+1)(x+3)(x+5)-20
=[(x-1)(x+5)][(x+1)(x+3)]-20
=(x²+4x-5)(x²+4x+3)-24
=(x²+4x)²-5(x²+4x)+3(x²+4x)-15-20
=(x²+4x)²-2(x²+4x)-35
=(x²+4x+5)(x²+4x-7)

因式分解:(x-1)(x+1)(x+3)(x+5)+16

解:(x+1)(x-1)(x+3)(x+5)+16 =(x+1)(x+3)(x-1)(x+5)+16 =(xx+4x+3)(xx+4x-5)+16 =(xx+4x)^2-2(xx+4x)-15+16 =(xx+4x)^2-2(xx+4x)+1=(xx+4x-1)^2 注：(x+1)(x+3)=xx+4x+3 (x-1)(x+5)=xx+4x-5

因式分解：（x-1)(x+3)+4

（x-1)(x+3)+4
=x²+2x-3+4
=x²+2x+1
=(x+1)²

(x-1)(x+3)+4,用因式分解

因式分解：(x-1)(x+3)+4=x+2x-3+4=x+2x+1=（x+1）望采纳

因式分解法(x+3)(x-1)=(x+3)

解方程：
(x+3)(x-1)=(x+3)
x²+2x-3=x+3
x²+2x-3-x-3=0
x²+x-6=0
（x+3)(x-2)=0
x+3=0 或 x-2=0
x=－3 或 x=2