4a表示四个a相乘对不对 已知a^2+4a+1=0,并且有（a^4+ma^2+1)/(2a^3+ma^2+2a)=3,求m的值？

已知a^2+4a+1=0,并且有（a^4+ma^2+1)/(2a^3+ma^2+2a)=3,求m的值？  

已知a^2+4a+1=0,并且有（a^4+ma^2+1)/(2a^3+ma^2+2a)=3,求m的值？

a^2=-4a-1
a^4=(-4a-1)^2=16a^2+8a+1=16(-4a-1)+8a+1=-56a-15
a^3=a^2*a=a(-4a-1)=-4a^2-a=-4(-4a-1)-a=15a+4
(a^4+ma^2+1)/(2a^3+ma^2+2a)=3
a^4+ma^2+1=6a^3+3ma^2+6a
所以-56a-15+m(-4a-1)+1=6(15a+4)+3m(-4a-1)+6a
m(-4a-1+12a+3)=90a+6a+56a+24+15-1
m(8a+2)=152a+38
2m(4a+1)=38(4a+1)
m=19

若a^2+4a+1=0且(a^4+ma^2+1)/(2a^3+ma^2+2a)=3 求m的值

a^2=-4a-1
a^3=a^2*a=-4a^2-a=-4(-4a-1)-a=16a+4-a=15a+4
a^4=(a^2)^2=16a^2+8a+1=16(-4a-1)+8a+1=-56a-15
(a^4+ma^2+1)/2a^3+ma^2+2a=3
a^4+ma^2+1=6a^3+3ma^2+6a
2ma^2=-6a^3-6a+a^4+1
-8am-2m=-90a-24-6a-56a-15+1=-152a-38
2m(4a+1)=38(4a+1)
m=19

若a^2+4a+1=0且(a^4+ma^2+1)/(2a^3+ma^2+2a)=5求m的值

a^2+4a+1=0
a²+1=4a
两边同除以a得：
a+1/a=4
两边平方得：
a²+1/a²=16-2=14
(a^4+ma^2+1)/(2a^3+ma^2+2a)=5
分子分母同除以x²得：
(a²+1/a²+4m)/(2a+2/a+m)=5
(14+4m)/(8+m)=5
14+4m=40+5m
m=14-40
m=-26

已知a^2+4a+1=0，且(a^4+ma^2+1)/(2a^3+ma^2+2a)=3，试确定m得值？

解：a^2=-4a-1
a^3=a^2*a=-4a^2-a=-4(-4a-1)-a=16a+4-a=15a+4
a^4=(a^2)^2=16a^2+8a+1=16(-4a-1)+8a+1=-56a-15
(a^4+ma^2+1)/2a^3+ma^2+2a=3
a^4+ma^2+1=6a^3+3ma^2+6a
2ma^2=-6a^3-6a+a^4+1
-8am-2m=-90a-24-6a-56a-15+1=-152a-38
2m(4a+1)=38(4a+1)
m=19

若a^2+4a+1=0且(a^4+ma^2+1)/(3a^3+ma^2+3a)=5 求m的值

由已知得 a^4+ma^2+1=5（3a^3+ma^2+3a）=15a^3+5ma^2+15a，a^4-15a^3-4ma^2+1-15a+1=0
a^4-15a^3-4ma^2+1-15a+1=(a^2+4a+1)(a^2-19a+1)+74a^2-4ma^2=0
因为a^2+4a+1=0,可得74a^2-4ma^2=0
解方程a^2+4a+1=0，可得a不等于0，则74-4m=0，解得m=18.5

已知a2+4a+1=0,且a4+ma2+1/2a3+ma2+2a=3,试确定m的值．

5/2

已知a*a+4a+1=0，且(a*a*a*a-ma*a+1)/(2a*a*a+ma*a+2a)=3 求m的值拜托各位大神

a*a+4a+1=0；a^2+1=-4a a^4+1+2a^2=(-4a)^2=16a^2 a^4+1=14a^2 2a^3+2a=-8a^2 (a*a*a*a-ma*a+1)/(2a*a*a+ma*a+2a)=3 =(14-m)/(m-8) m=19/2

已知a²+4a+1=0，且（a四次方+ma²+1）÷（2a³+ma²+2a）=3，求m的值

a^2+4a+1=0
a^2=-4a-1
a^3=a^2*a=-4a^2-a=-4(-4a-1)-a=16a+4-a=15a+4
a^4=(a^2)^2=16a^2+8a+1=16(-4a-1)+8a+1=-56a-15
(a^4+ma^2+1)/(2a^3+ma^2+2a)=3
a^4+ma^2+1=6a^3+3ma^2+6a
2ma^2=-6a^3-6a+a^4+1
把a^2，a^3，a^4分别代入，得：
-8am-2m=-90a-24-6a-56a-15+1
-8am-2m=-152a-38
2m(4a+1)=38(4a+1)
m=19