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log3² 3^a=2,则log3 8-2log 3 6=?

火烧 2021-11-18 22:39:09 1095
3^a=2,则log3 8-2log 3 6=? 3^a=2,则log3 8-2log 3 6=?3^a=2a=log3 2log3 8-2log 3 6=log3 2^3-2log 3 2*3=3l

3^a=2,则log3 8-2log 3 6=?  

3^a=2,则log3 8-2log 3 6=?

3^a=2
a=log3 2
log3 8-2log 3 6
=log3 2^3-2log 3 2*3
=3log3 2-2(log3 2+log3 3)
=3a-2(a+1)
=a-2

计算:2-3=______,(-a2)3+(-a3)2=______

2-3=

1 23

=

1 8


(-a2)3+(-a3)2=-a6+a6=0;
故答案为:

1 8

、0.

5(3x-1)-3(4x-3)=10

解:
5(3x-1)-3(4x-3)=10
15x-5-12x+9=10
3x+4=10
3x=6
x=2

(x05-3)05-3(3-x05)+2=0

解:
(x²-3)²-3(3-x²)+2=0
(x²-3)²+3(x²-3)+2=0
(x²-3+2)(x²-3+1)=0
(x²-1)(x²-2)=0
(x+1)(x-1)(x+√2)(x-√2)=0
x=-1或x=1或x=-√2或x=√2

3x+3(x-1)+3(x+1)=207

3x+3(x-1)+3(x+1)=207
3x+3x-3+3x+3=207
9x=207
x=207÷9
x=23

2(3x+1)²=3(3x+1)

2(3x+1)²=3(3x+1)
2(3x+1)²-3(3x+1)=0
(3x+1)(6x+2-3)=0
x=-1/3 x=1/6

√12 |√3-3|-2sin60°-(√3)²+ 2016°

原式=2√3(3-√3)-2x√3/2-3+1
=6√3-6-√3-3+1
=5√3-8
行家正解,不明白可以追问!祝您学习进步
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log3² 3^a=2,则log3 8-2log 3 6=?

(-x)^6-(3x^3)^2+8[(-x)^3]^2

(-x)^6-(3x^3)^2+8[(-x)^3]^2
解:
原式=
(-x)^6-(3x^3)^2+8[(-x)^3]^2
x^6-9x^6+8x^6
=(1+8-9)x^6
=0

(x加3)加(3x加3)等于50

(x+3)+(3x+3)=50
4x+6=50
4x=50-6=44
x=44/4=11

1+2×3+3×32+…+n×3n-1=______

设Sn=1+2×3+3×32+…+n×3n-1 ①
∴3Sn=3+2×32+3×33+…+(n-1)×3n-1+n×3n②
①-②得,-2Sn=1+3+32+…+3n-1-n×3n
=

1?3n 1?3

-n×3n
=?

(2n?1)?3n+1 2


∴Sn=

(2n?1)?3n+1 4

故答案为:

(2n?1)?3n+1 4

  
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